Question

$$\sqrt{ 1+ \sqrt{ 1+ \sqrt{ 1+ \sqrt{ 64 } } } }$$

Answer

sqrt(3)

Solution


Since \(8\times 8=64\), the square root of \(64\) is \(8\).
\[\sqrt{1+\sqrt{1+\sqrt{1+8}}}\]
Simplify  \(1+8\)  to  \(9\).
\[\sqrt{1+\sqrt{1+\sqrt{9}}}\]
Since \(3\times 3=9\), the square root of \(9\) is \(3\).
\[\sqrt{1+\sqrt{1+3}}\]
Simplify  \(1+3\)  to  \(4\).
\[\sqrt{1+\sqrt{4}}\]
Since \(2\times 2=4\), the square root of \(4\) is \(2\).
\[\sqrt{1+2}\]
Simplify  \(1+2\)  to  \(3\).
\[\sqrt{3}\]

Decimal Form: 1.732051