Question

$$\sqrt{2-7x}-2x=0$$

Answer

x=1/4

Solution


Separate terms with roots from terms without roots.
\[\sqrt{2-7x}=2x\]
Square both sides.
\[2-7x=4{x}^{2}\]
Move all terms to one side.
\[2-7x-4{x}^{2}=0\]
Multiply both sides by \(-1\).
\[4{x}^{2}+7x-2=0\]
Split the second term in \(4{x}^{2}+7x-2\) into two terms.
\[4{x}^{2}+8x-x-2=0\]
Factor out common terms in the first two terms, then in the last two terms.
\[4x(x+2)-(x+2)=0\]
Factor out the common term \(x+2\).
\[(x+2)(4x-1)=0\]
Solve for \(x\).
\[x=-2,\frac{1}{4}\]
Check solution
When \(x=-2\), the original equation \(\sqrt{2-7x}-2x=0\) does not hold true.We will drop \(x=-2\) from the solution set.
Therefore,
\(x=\frac{1}{4}\)

Decimal Form: 0.25