Solve sqrt(2025) + sqrt(0.0612 + x) = 45.24 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\sqrt{2025}+\sqrt{0.0612+x}=45.24$$

Solve for x

$x=-0.0036$

Steps for Solving Radical Equations

Subtract $\sqrt{2025}$ from both sides of the equation.

$$\sqrt{x+0.0612}+\sqrt{2025}-\sqrt{2025}=45.24-\sqrt{2025}$$

Subtracting $\sqrt{2025}$ from itself leaves $0$.

$$\sqrt{x+0.0612}=45.24-\sqrt{2025}$$

Subtract $\sqrt{2025}$ from $45.24$.

$$\sqrt{x+0.0612}=0.24$$

Square both sides of the equation.

$$x+0.0612=0.0576$$

Subtract $0.0612$ from both sides of the equation.

$$x+0.0612-0.0612=0.0576-0.0612$$

Subtracting $0.0612$ from itself leaves $0$.

$$x=0.0576-0.0612$$

Subtract $0.0612$ from $0.0576$ by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.

$$x=-0.0036$$