Solve sqrt(25)+4-5+(4)^(2)+25-root(3,-64) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\sqrt{ 25 } +4-5+ { 4 }^{ 2 } +25- \sqrt[ 3 ]{ -64 }$$

Evaluate

$49$

Solution Steps

Calculate the square root of $25$ and get $5$.

$$5+4-5+4^{2}+25-\sqrt[3]{-64}$$

Add $5$ and $4$ to get $9$.

$$9-5+4^{2}+25-\sqrt[3]{-64}$$

Subtract $5$ from $9$ to get $4$.

$$4+4^{2}+25-\sqrt[3]{-64}$$

Calculate $4$ to the power of $2$ and get $16$.

$$4+16+25-\sqrt[3]{-64}$$

Add $4$ and $16$ to get $20$.

$$20+25-\sqrt[3]{-64}$$

Add $20$ and $25$ to get $45$.

$$45-\sqrt[3]{-64}$$

Calculate $\sqrt[3]{-64}$ and get $-4$.

$$45-\left(-4\right)$$

The opposite of $-4$ is $4$.

$$45+4$$

Add $45$ and $4$ to get $49$.

$$49$$

Factor

$7^{2}$