Combine $\sqrt{3}$ and $\frac{\sqrt{3}}{3}$ to get $\frac{4}{3}\sqrt{3}$.
$$\frac{4}{3}\sqrt{3}-\frac{1}{\sqrt{27}}$$
Factor $27=3^{2}\times 3$. Rewrite the square root of the product $\sqrt{3^{2}\times 3}$ as the product of square roots $\sqrt{3^{2}}\sqrt{3}$. Take the square root of $3^{2}$.
$$\frac{4}{3}\sqrt{3}-\frac{1}{3\sqrt{3}}$$
Rationalize the denominator of $\frac{1}{3\sqrt{3}}$ by multiplying numerator and denominator by $\sqrt{3}$.
