How to solve sqrt(3/2)-1/2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve sqrt(3/2)-1/2 | Equatix

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$$\sqrt{ 3/2 } -1/2$$

$\frac{\sqrt{6}-1}{2}\approx 0.724744871$

Rewrite the square root of the division $\sqrt{\frac{3}{2}}$ as the division of square roots $\frac{\sqrt{3}}{\sqrt{2}}$.

$$\frac{\sqrt{3}}{\sqrt{2}}-\frac{1}{2}$$

Rationalize the denominator of $\frac{\sqrt{3}}{\sqrt{2}}$ by multiplying numerator and denominator by $\sqrt{2}$.

$$\frac{\sqrt{3}\sqrt{2}}{\left(\sqrt{2}\right)^{2}}-\frac{1}{2}$$

The square of $\sqrt{2}$ is $2$.

$$\frac{\sqrt{3}\sqrt{2}}{2}-\frac{1}{2}$$

To multiply $\sqrt{3}$ and $\sqrt{2}$, multiply the numbers under the square root.

$$\frac{\sqrt{6}}{2}-\frac{1}{2}$$

Since $\frac{\sqrt{6}}{2}$ and $\frac{1}{2}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{\sqrt{6}-1}{2}$$

$\frac{\sqrt{6} - 1}{2} = 0.7247448713915889$