Question

$$\sqrt{3136}+\sqrt{13824+\sqrt{4489}$$

Answer

123+48*sqrt(6)

Solution


Since \(56\times 56=3136\), the square root of \(3136\) is \(56\).
\[56+\sqrt{13824}+\sqrt{4489}\]
Simplify  \(\sqrt{13824}\)  to  \(48\sqrt{6}\).
\[56+48\sqrt{6}+\sqrt{4489}\]
Since \(67\times 67=4489\), the square root of \(4489\) is \(67\).
\[56+48\sqrt{6}+67\]
Simplify.
\[123+48\sqrt{6}\]

Decimal Form: 240.575508