How to solve sqrt(3x + 4) = 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve sqrt(3x + 4) = 2 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\sqrt{3x+4}=2$$

Solve for x

$x=0$

Steps for Solving Radical Equations

Square both sides of the equation.

$$3x+4=4$$

Subtract $4$ from both sides of the equation.

$$3x+4-4=4-4$$

Subtracting $4$ from itself leaves $0$.

$$3x=4-4$$

Subtract $4$ from $4$.

$$3x=0$$

Divide both sides by $3$.

$$\frac{3x}{3}=\frac{0}{3}$$

Dividing by $3$ undoes the multiplication by $3$.

$$x=\frac{0}{3}$$

Divide $0$ by $3$.

$$x=0$$

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Question

Solve for x

Steps for Solving Radical Equations