Question

$$\sqrt{ 450 } + \sqrt{ 12 } - \sqrt{ 48 } + \sqrt{ 98 }$$

Answer

22*sqrt(2)-2*sqrt(3)

Solution


Simplify  \(\sqrt{450}\)  to  \(15\sqrt{2}\).
\[15\sqrt{2}+\sqrt{12}-\sqrt{48}+\sqrt{98}\]
Simplify  \(\sqrt{12}\)  to  \(2\sqrt{3}\).
\[15\sqrt{2}+2\sqrt{3}-\sqrt{48}+\sqrt{98}\]
Simplify  \(\sqrt{48}\)  to  \(4\sqrt{3}\).
\[15\sqrt{2}+2\sqrt{3}-4\sqrt{3}+\sqrt{98}\]
Simplify  \(\sqrt{98}\)  to  \(7\sqrt{2}\).
\[15\sqrt{2}+2\sqrt{3}-4\sqrt{3}+7\sqrt{2}\]
Collect like terms.
\[(15\sqrt{2}+7\sqrt{2})+(2\sqrt{3}-4\sqrt{3})\]
Simplify.
\[22\sqrt{2}-2\sqrt{3}\]

Decimal Form: 27.648597