Question

$$\sqrt{ 4m } = \frac{ { \left((2) \right) }^{ 2 } -5 }{ 2 }$$

Answer

[No Solution]

Solution


Remove parentheses.
\[\sqrt{4m}=\frac{{2}^{2}-5}{2}\]
Use this rule: \(\sqrt{ab}=\sqrt{a}\sqrt{b}\).
\[\sqrt{4}\sqrt{m}=\frac{{2}^{2}-5}{2}\]
Since \(2\times 2=4\), the square root of \(4\) is \(2\).
\[2\sqrt{m}=\frac{{2}^{2}-5}{2}\]
Simplify  \({2}^{2}\)  to  \(4\).
\[2\sqrt{m}=\frac{4-5}{2}\]
Simplify  \(4-5\)  to  \(-1\).
\[2\sqrt{m}=\frac{-1}{2}\]
Move the negative sign to the left.
\[2\sqrt{m}=-\frac{1}{2}\]
Square both sides.
\[4m=\frac{1}{4}\]
Divide both sides by \(4\).
\[m=\frac{\frac{1}{4}}{4}\]
Simplify  \(\frac{\frac{1}{4}}{4}\)  to  \(\frac{1}{4\times 4}\).
\[m=\frac{1}{4\times 4}\]
Simplify  \(4\times 4\)  to  \(16\).
\[m=\frac{1}{16}\]
Check solution
When \(m=\frac{1}{16}\), the original equation \(\sqrt{4m}=\frac{{2}^{2}-5}{2}\) does not hold true.We will drop \(m=\frac{1}{16}\) from the solution set.
Therefore,
No solution exists.