Factor $24=2^{2}\times 6$. Rewrite the square root of the product $\sqrt{2^{2}\times 6}$ as the product of square roots $\sqrt{2^{2}}\sqrt{6}$. Take the square root of $2^{2}$.
$$\sqrt{6}+7+2\sqrt{6}$$
Combine $\sqrt{6}$ and $2\sqrt{6}$ to get $3\sqrt{6}$.
