Question

$$\sqrt{ 64 { x }^{ 3 } +12 { x }^{ 2 } 6x+ }$$

Answer

$$sqrt(136*x^3+1)$$

Solution


Collect like terms.
\[\sqrt{64{x}^{3}+(72{x}^{3}+1)}\]
Remove parentheses.
\[\sqrt{64{x}^{3}+72{x}^{3}+1}\]
Collect like terms.
\[\sqrt{(64{x}^{3}+72{x}^{3})+1}\]
Simplify  \((64{x}^{3}+72{x}^{3})+1\)  to  \(136{x}^{3}+1\).
\[\sqrt{136{x}^{3}+1}\]