$$\sqrt { 64 } - \frac { ( \sqrt [ 3 ] { 27 } ) ^ { 2 } } { 9 } + \sqrt { 25 }$$
$12$
$$8-\frac{\left(\sqrt[3]{27}\right)^{2}}{9}+\sqrt{25}$$
$$8-\frac{3^{2}}{9}+\sqrt{25}$$
$$8-\frac{9}{9}+\sqrt{25}$$
$$8-1+\sqrt{25}$$
$$7+\sqrt{25}$$
$$7+5$$
$$12$$
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$2^{2}\times 3$
