Question

$$\sqrt{ { -2 }^{ 2 } } + \sqrt[ 3 ]{ { -2 }^{ 3 } } +4 \sqrt{ { -2 }^{ 4 } }$$

Answer

16

Solution


Since the power of 2 is even, the result will be positive.
\[\sqrt{{2}^{2}}+\sqrt[3]{{(-2)}^{3}}+4\sqrt{{(-2)}^{4}}\]
Simplify  \(\sqrt{{2}^{2}}\)  to  \(2\).
\[2+\sqrt[3]{{(-2)}^{3}}+4\sqrt{{(-2)}^{4}}\]
Since the power of 3 is odd, the result will be negative.
\[2+\sqrt[3]{-{2}^{3}}+4\sqrt{{(-2)}^{4}}\]
Simplify  \({2}^{3}\)  to  \(8\).
\[2+\sqrt[3]{-8}+4\sqrt{{(-2)}^{4}}\]
Since the power of 4 is even, the result will be positive.
\[2+\sqrt[3]{-8}+4\sqrt{{2}^{4}}\]
Simplify  \(\sqrt{{2}^{4}}\)  to  \({2}^{2}\).
\[2+\sqrt[3]{-8}+4\times {2}^{2}\]
Simplify exponent.
\[2-2+4\times {2}^{2}\]
Simplify  \({2}^{2}\)  to  \(4\).
\[2-2+4\times 4\]
Simplify  \(4\times 4\)  to  \(16\).
\[2-2+16\]
Simplify  \(2-2\)  to  \(0\).
\[0+16\]
Simplify.
\[16\]