Question

$$\sqrt{ { -2 }^{ 2 } } + \sqrt[ 3 ]{ { -2 }^{ 3 } } + \sqrt[ 4 ]{ { -2 }^{ 4 } }$$

Answer

2

Solution


Since the power of 2 is even, the result will be positive.
\[\sqrt{{2}^{2}}+\sqrt[3]{{(-2)}^{3}}+\sqrt[4]{{(-2)}^{4}}\]
Simplify  \(\sqrt{{2}^{2}}\)  to  \(2\).
\[2+\sqrt[3]{{(-2)}^{3}}+\sqrt[4]{{(-2)}^{4}}\]
Since the power of 3 is odd, the result will be negative.
\[2+\sqrt[3]{-{2}^{3}}+\sqrt[4]{{(-2)}^{4}}\]
Simplify  \({2}^{3}\)  to  \(8\).
\[2+\sqrt[3]{-8}+\sqrt[4]{{(-2)}^{4}}\]
Since the power of 4 is even, the result will be positive.
\[2+\sqrt[3]{-8}+\sqrt[4]{{2}^{4}}\]
Simplify exponent.
\[2-2+\sqrt[4]{{2}^{4}}\]
Use this rule: \(\sqrt[4]{{x}^{4}}=x\).
\[2-2+2\]
Simplify  \(2-2\)  to  \(0\).
\[0+2\]
Simplify.
\[2\]