Question

$$\sqrt{}x=5; y^{2}-119=10y$$

Answer

x=25;y=17,-7

Solution


Solve for \(x\) in \(\sqrt{x}=5\).
\[x=25\]
Substitute \(x=25\) into \({y}^{2}-119=10y\).
\[{y}^{2}-119=10y\]
Solve for \(y\) in \({y}^{2}-119=10y\).
\[y=17,-7\]
Therefore,
\[\begin{aligned}&x=25\\&y=17,-7\end{aligned}\]