Question

$$\sqrt{ \frac{ 4 }{ 9 } } + \sqrt{ \frac{ 1 }{ 9 } }$$

Answer

1

Solution


Simplify  \(\sqrt{\frac{4}{9}}\)  to  \(\frac{\sqrt{4}}{\sqrt{9}}\).
\[\frac{\sqrt{4}}{\sqrt{9}}+\sqrt{\frac{1}{9}}\]
Since \(2\times 2=4\), the square root of \(4\) is \(2\).
\[\frac{2}{\sqrt{9}}+\sqrt{\frac{1}{9}}\]
Since \(3\times 3=9\), the square root of \(9\) is \(3\).
\[\frac{2}{3}+\sqrt{\frac{1}{9}}\]
Simplify  \(\sqrt{\frac{1}{9}}\)  to  \(\frac{\sqrt{1}}{\sqrt{9}}\).
\[\frac{2}{3}+\frac{\sqrt{1}}{\sqrt{9}}\]
Simplify  \(\sqrt{1}\)  to  \(1\).
\[\frac{2}{3}+\frac{1}{\sqrt{9}}\]
Since \(3\times 3=9\), the square root of \(9\) is \(3\).
\[\frac{2}{3}+\frac{1}{3}\]
Simplify.
\[1\]