1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 41 441 | Equatix

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Question

$$\sqrt { \frac { 41 } { 4 - 1 } }$$

$\frac{\sqrt{123}}{3}\approx 3.696845502$

Subtract $1$ from $4$ to get $3$.

$$\sqrt{\frac{41}{3}}$$

Rewrite the square root of the division $\sqrt{\frac{41}{3}}$ as the division of square roots $\frac{\sqrt{41}}{\sqrt{3}}$.

$$\frac{\sqrt{41}}{\sqrt{3}}$$

Rationalize the denominator of $\frac{\sqrt{41}}{\sqrt{3}}$ by multiplying numerator and denominator by $\sqrt{3}$.

$$\frac{\sqrt{41}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}$$

The square of $\sqrt{3}$ is $3$.

$$\frac{\sqrt{41}\sqrt{3}}{3}$$

To multiply $\sqrt{41}$ and $\sqrt{3}$, multiply the numbers under the square root.

$$\frac{\sqrt{123}}{3}$$