$$\sqrt{ m } -2=n$$
$m=\left(n+2\right)^{2}$
$n+2\geq 0$
$m=\left(n+2\right)^{2}$
$n=-2\text{ or }arg(n+2)<\pi $
$n=\sqrt{m}-2$
$n=\sqrt{m}-2$
$m\geq 0$