Solve sqrt(-5+5\times6-2(-9+28/4)-(1)^(8)) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\sqrt{ -5+5 \times 6-2(-9+28/4)- { 1 }^{ 8 } }$$

Evaluate

$2\sqrt{7}\approx 5.291502622$

Solution Steps

Multiply $5$ and $6$ to get $30$.

$$\sqrt{-5+30-2\left(-9+\frac{28}{4}\right)-1^{8}}$$

Add $-5$ and $30$ to get $25$.

$$\sqrt{25-2\left(-9+\frac{28}{4}\right)-1^{8}}$$

Divide $28$ by $4$ to get $7$.

$$\sqrt{25-2\left(-9+7\right)-1^{8}}$$

Add $-9$ and $7$ to get $-2$.

$$\sqrt{25-2\left(-2\right)-1^{8}}$$

Multiply $2$ and $-2$ to get $-4$.

$$\sqrt{25-\left(-4\right)-1^{8}}$$

The opposite of $-4$ is $4$.

$$\sqrt{25+4-1^{8}}$$

Add $25$ and $4$ to get $29$.

$$\sqrt{29-1^{8}}$$

Calculate $1$ to the power of $8$ and get $1$.

$$\sqrt{29-1}$$

Subtract $1$ from $29$ to get $28$.

$$\sqrt{28}$$

Factor $28=2^{2}\times 7$. Rewrite the square root of the product $\sqrt{2^{2}\times 7}$ as the product of square roots $\sqrt{2^{2}}\sqrt{7}$. Take the square root of $2^{2}$.

$$2\sqrt{7}$$