Since \(7\times 7=49\), the square root of \(49\) is \(7\).
\[\begin{aligned}&\sqrt{7+\sqrt{8}}\\&\sqrt{16}\end{aligned}\]
Simplify \(\sqrt{8}\) to \(2\sqrt{2}\).
\[\begin{aligned}&\sqrt{7+2\sqrt{2}}\\&\sqrt{16}\end{aligned}\]
Since \(4\times 4=16\), the square root of \(16\) is \(4\).
\[\begin{aligned}&\sqrt{7+2\sqrt{2}}\\&4\end{aligned}\]
sqrt(7+2*sqrt(2));4
