Question

$$\sqrt{x}+a=b$$

Solve for a (complex solution)

$a=b-\sqrt{x}$

Solve for b (complex solution)

$b=a+\sqrt{x}$

Solve for a

$a=b-\sqrt{x}$
$x\geq 0$

Solve for b

$b=a+\sqrt{x}$
$x\geq 0$