Question

$$\sqrt { x ^ { 2 } + 3 x + 8 } + \sqrt { x ^ { 2 } + 3 x + 2 } = 3$$

Solve for x

$x=\frac{\sqrt{2}-3}{2}\approx -0.792893219$
$x=\frac{-\sqrt{2}-3}{2}\approx -2.207106781$