Question

$$\sqrt{x^{2}+}a^{2}=b$$

Answer

$$x=b-a^2$$

Solution


Use this rule: \({\sqrt{x}}^{2}=x\).
\[x+{a}^{2}=b\]
Subtract \({a}^{2}\) from both sides.
\[x=b-{a}^{2}\]