How to solve sqrt(y+4)-3=2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve sqrt(y+4)-3=2 | Equatix

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Question

$$\sqrt{ y+4 } -3=2$$

Solve for y

$y=21$

Steps for Solving Radical Equations

Add $3$ to both sides of the equation.

$$\sqrt{y+4}-3-\left(-3\right)=2-\left(-3\right)$$

Subtracting $-3$ from itself leaves $0$.

$$\sqrt{y+4}=2-\left(-3\right)$$

Subtract $-3$ from $2$.

$$\sqrt{y+4}=5$$

Square both sides of the equation.

$$y+4=25$$

Subtract $4$ from both sides of the equation.

$$y+4-4=25-4$$

Subtracting $4$ from itself leaves $0$.

$$y=25-4$$

Subtract $4$ from $25$.

$$y=21$$

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Question

Solve for y

Steps for Solving Radical Equations