$$\sum_{n=1}^{d}(\frac{n}{in})^{n}$$
$\frac{j\times \left(\frac{1}{j}\right)^{d+1}-1}{1-j}$
$\frac{dj\times \left(\frac{1}{j}\right)^{d+1}+j\times \left(\frac{1}{j}\right)^{d+1}-d\times \left(\frac{1}{j}\right)^{d+1}-1}{\left(1-j\right)^{2}}$
