Solve T = 3x ^ 2 - 3 + 5x + 4x ^ 2 - 7 - 8R | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$T=3x^{2}-3+5x+4x^{2}-7-8R$$

Solve for R

$R=\frac{7x^{2}}{8}+\frac{5x}{8}-\frac{T}{8}-\frac{5}{4}$

Steps for Solving Linear Equation

Combine $3x^{2}$ and $4x^{2}$ to get $7x^{2}$.

$$T=7x^{2}-3+5x-7-8R$$

Subtract $7$ from $-3$ to get $-10$.

$$T=7x^{2}-10+5x-8R$$

Swap sides so that all variable terms are on the left hand side.

$$7x^{2}-10+5x-8R=T$$

Subtract $7x^{2}$ from both sides.

$$-10+5x-8R=T-7x^{2}$$

Add $10$ to both sides.

$$5x-8R=T-7x^{2}+10$$

Subtract $5x$ from both sides.

$$-8R=T-7x^{2}+10-5x$$

The equation is in standard form.

$$-8R=10+T-5x-7x^{2}$$

Divide both sides by $-8$.

$$\frac{-8R}{-8}=\frac{10+T-5x-7x^{2}}{-8}$$

Dividing by $-8$ undoes the multiplication by $-8$.

$$R=\frac{10+T-5x-7x^{2}}{-8}$$

Divide $T-7x^{2}+10-5x$ by $-8$.

$$R=\frac{7x^{2}}{8}+\frac{5x}{8}-\frac{T}{8}-\frac{5}{4}$$

Solve for T

$T=7x^{2}+5x-8R-10$