$$t-(2t+5)-5(1-2t)=2(3+4t)-3(t-4)$$
$t=7$
$$t-2t-5-5\left(1-2t\right)=2\left(3+4t\right)-3\left(t-4\right)$$
$$-t-5-5\left(1-2t\right)=2\left(3+4t\right)-3\left(t-4\right)$$
$$-t-5-5+10t=2\left(3+4t\right)-3\left(t-4\right)$$
$$-t-10+10t=2\left(3+4t\right)-3\left(t-4\right)$$
$$9t-10=2\left(3+4t\right)-3\left(t-4\right)$$
$$9t-10=6+8t-3\left(t-4\right)$$
$$9t-10=6+8t-3t+12$$
$$9t-10=6+5t+12$$
$$9t-10=18+5t$$
$$9t-10-5t=18$$
$$4t-10=18$$
$$4t=18+10$$
$$4t=28$$
$$t=\frac{28}{4}$$
$$t=7$$
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