$$\tan\ 20+\frac{3}{13}.; \frac{5}{10}; \frac{5}{12}; \frac{12}{13}; \frac{13}{12}$$
$2$
$$\frac{8+\frac{1}{8}-\frac{1}{8}}{4}$$
$$\frac{\frac{64}{8}+\frac{1}{8}-\frac{1}{8}}{4}$$
$$\frac{\frac{64+1}{8}-\frac{1}{8}}{4}$$
$$\frac{\frac{65}{8}-\frac{1}{8}}{4}$$
$$\frac{\frac{65-1}{8}}{4}$$
$$\frac{\frac{64}{8}}{4}$$
$$\frac{8}{4}$$
$$2$$
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