Question

$$Theareaofarec \tan gleis 162 \frac { 1 } { 2 }$$

Answer

$$81*Th*e^4*IM*a^4*r^2*o*f*c*t*n*g*l*s$$

Solution


Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{Theareaofarectangle\imath s\times 162\times 1}{2}\]
Regroup terms.
\[\frac{162aaaarrofctnglsTheeee\imath }{2}\]
Simplify  \(162aaaarrofctnglsTheeee\imath \)  to  \(162{a}^{4}{r}^{2}ofctnglsTheeee\imath \).
\[\frac{162{a}^{4}{r}^{2}ofctnglsTheeee\imath }{2}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{162{a}^{4}{r}^{2}ofctnglsTh{e}^{4}\imath }{2}\]
Regroup terms.
\[\frac{162Th{e}^{4}\imath {a}^{4}{r}^{2}ofctngls}{2}\]
Simplify.
\[81Th{e}^{4}\imath {a}^{4}{r}^{2}ofctngls\]