$$u^{3}-3u+9); (u^{4}-3u^{3}+2u+6)+(u^{4}-3u^{2}+6u+2)-$$
$3\left(u^{2}-1\right)$
$$3u^{3-1}-3u^{1-1}$$
$$3u^{2}-3u^{1-1}$$
$$3u^{2}-3u^{0}$$
$$3u^{2}-3$$
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$u^{3}-3u+9$
