Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\vdash\vdash[x]=\frac{1}{(s^{2}+w^{2})}[\frac{s}{s^{2}+n^{2}}+s]$$

Answer

$$w=((v^2*d^2*a^2*s^2*h*h[x]-n^2-s])/s^2-s^2)^(1/2[s)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
v^2*d^2*a^2*s^2*h*h\(x\)=1*(s^2+w^2)\(s{s}^{2}+{n}^{2}+s\)
v^2*d^2*a^2*s^2*h*h\(x\)=s^2*(s^2+w^2)\(s+{n}^{2}+s\)
Subtract \({n}^{2}\) from both sides.
v^2*d^2*a^2*s^2*h*h\(x\)-n^2=s^2*(s^2+w^2)\(s+s\)
Divide both sides by \({s}^{2}\).
Subtract \({s}^{2}\) from both sides.
Switch sides.
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