How to solve x/3+x/4+18000=x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x/3+x/4+18000=x | Equatix

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$$x/3+x/4+18000=x$$

$x=43200$

Combine $\frac{x}{3}$ and $\frac{x}{4}$ to get $\frac{7}{12}x$.

$$\frac{7}{12}x+18000=x$$

Subtract $x$ from both sides.

$$\frac{7}{12}x+18000-x=0$$

Combine $\frac{7}{12}x$ and $-x$ to get $-\frac{5}{12}x$.

$$-\frac{5}{12}x+18000=0$$

Subtract $18000$ from both sides. Anything subtracted from zero gives its negation.

$$-\frac{5}{12}x=-18000$$

Multiply both sides by $-\frac{12}{5}$, the reciprocal of $-\frac{5}{12}$.

$$x=-18000\left(-\frac{12}{5}\right)$$

Express $-18000\left(-\frac{12}{5}\right)$ as a single fraction.

$$x=\frac{-18000\left(-12\right)}{5}$$

Multiply $-18000$ and $-12$ to get $216000$.

$$x=\frac{216000}{5}$$

Divide $216000$ by $5$ to get $43200$.

$$x=43200$$