Regroup terms.
\[x=2-\sqrt{3}\imath fnda-\frac{1}{a}\]
Subtract \(2\) from both sides.
\[x-2=-\sqrt{3}\imath fnda-\frac{1}{a}\]
Regroup terms.
\[x-2=-\frac{1}{a}-\sqrt{3}\imath fnda\]
Add \(\frac{1}{a}\) to both sides.
\[x-2+\frac{1}{a}=-\sqrt{3}\imath fnda\]
Divide both sides by \(-\sqrt{3}\).
\[-\frac{x-2+\frac{1}{a}}{\sqrt{3}}=\imath fnda\]
Divide both sides by \(\imath \).
\[-\frac{\frac{x-2+\frac{1}{a}}{\sqrt{3}}}{\imath }=fnda\]
Simplify \(\frac{\frac{x-2+\frac{1}{a}}{\sqrt{3}}}{\imath }\) to \(\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath }\).
\[-\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath }=fnda\]
Divide both sides by \(n\).
\[-\frac{\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath }}{n}=fda\]
Simplify \(\frac{\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath }}{n}\) to \(\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath n}\).
\[-\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath n}=fda\]
Divide both sides by \(d\).
\[-\frac{\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath n}}{d}=fa\]
Simplify \(\frac{\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath n}}{d}\) to \(\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath nd}\).
\[-\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath nd}=fa\]
Divide both sides by \(a\).
\[-\frac{\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath nd}}{a}=f\]
Simplify \(\frac{\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath nd}}{a}\) to \(\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath nda}\).
\[-\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath nda}=f\]
Switch sides.
\[f=-\frac{x-2+\frac{1}{a}}{\sqrt{3}\imath nda}\]
f=-(x-2+1/a)/(sqrt(3)*IM*n*d*a)
