Question

$$x = 3 + 2 \sqrt { 2 } x ^ { 3 } + \frac { 1 } { x ^ { 3 } }$$

Answer

$$n=(d/2-3/2-1/(2*x^3))/(Fi*sqrt(2)*d*x^3)$$

Solution


Regroup terms.
\[d=3+2Fi\sqrt{2}nd{x}^{3}+\frac{1}{{x}^{3}}\]
Simplify square root.
\[d=3+2\sqrt{2}Find{x}^{3}+\frac{1}{{x}^{3}}\]
Regroup terms.
\[d=3+2Fi\sqrt{2}nd{x}^{3}+\frac{1}{{x}^{3}}\]
Subtract \(3\) from both sides.
\[d-3=2Fi\sqrt{2}nd{x}^{3}+\frac{1}{{x}^{3}}\]
Simplify square root.
\[d-3=2\sqrt{2}Find{x}^{3}+\frac{1}{{x}^{3}}\]
Regroup terms.
\[d-3=2Fi\sqrt{2}nd{x}^{3}+\frac{1}{{x}^{3}}\]
Simplify square root.
\[d-3=2\sqrt{2}Find{x}^{3}+\frac{1}{{x}^{3}}\]
Subtract \(\frac{1}{{x}^{3}}\) from both sides.
\[d-3-\frac{1}{{x}^{3}}=2\sqrt{2}Find{x}^{3}\]
Regroup terms.
\[d-3-\frac{1}{{x}^{3}}=2Fi\sqrt{2}nd{x}^{3}\]
Simplify square root.
\[d-3-\frac{1}{{x}^{3}}=2\sqrt{2}Find{x}^{3}\]
Regroup terms.
\[d-3-\frac{1}{{x}^{3}}=2Fi\sqrt{2}nd{x}^{3}\]
Divide both sides by \(2\).
\[\frac{d-3-\frac{1}{{x}^{3}}}{2}=Fi\sqrt{2}nd{x}^{3}\]
Simplify  \(\frac{d-3-\frac{1}{{x}^{3}}}{2}\)  to  \(\frac{d}{2}-\frac{3}{2}-\frac{\frac{1}{{x}^{3}}}{2}\).
\[\frac{d}{2}-\frac{3}{2}-\frac{\frac{1}{{x}^{3}}}{2}=Fi\sqrt{2}nd{x}^{3}\]
Simplify  \(\frac{\frac{1}{{x}^{3}}}{2}\)  to  \(\frac{1}{2{x}^{3}}\).
\[\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}=Fi\sqrt{2}nd{x}^{3}\]
Divide both sides by \(Fi\).
\[\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi}=\sqrt{2}nd{x}^{3}\]
Divide both sides by \(\sqrt{2}\).
\[\frac{\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi}}{\sqrt{2}}=nd{x}^{3}\]
Simplify  \(\frac{\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi}}{\sqrt{2}}\)  to  \(\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi\sqrt{2}}\).
\[\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi\sqrt{2}}=nd{x}^{3}\]
Divide both sides by \(d\).
\[\frac{\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi\sqrt{2}}}{d}=n{x}^{3}\]
Simplify  \(\frac{\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi\sqrt{2}}}{d}\)  to  \(\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi\sqrt{2}d}\).
\[\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi\sqrt{2}d}=n{x}^{3}\]
Divide both sides by \({x}^{3}\).
\[\frac{\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi\sqrt{2}d}}{{x}^{3}}=n\]
Simplify  \(\frac{\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi\sqrt{2}d}}{{x}^{3}}\)  to  \(\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi\sqrt{2}d{x}^{3}}\).
\[\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi\sqrt{2}d{x}^{3}}=n\]
Switch sides.
\[n=\frac{\frac{d}{2}-\frac{3}{2}-\frac{1}{2{x}^{3}}}{Fi\sqrt{2}d{x}^{3}}\]