Question

$$x=7y+3=24y^{2}$$

Evaluate (complex solution)

$x=7y+3\text{ and }\left(y=\frac{\sqrt{337}+7}{48}\text{ or }y=\frac{7-\sqrt{337}}{48}\right)$

Solve for x

$\left\{\begin{matrix}x=\frac{193-7\sqrt{337}}{48}\text{, }&y=\frac{7-\sqrt{337}}{48}\\x=\frac{7\sqrt{337}+193}{48}\text{, }&y=\frac{\sqrt{337}+7}{48}\end{matrix}\right.$

Solve for y

$\left\{\begin{matrix}y=\frac{7-\sqrt{337}}{48}\text{, }&x=\frac{193-7\sqrt{337}}{48}\\y=\frac{\sqrt{337}+7}{48}\text{, }&x=\frac{7\sqrt{337}+193}{48}\end{matrix}\right.$