How to solve x = 9[x - 3]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x = 9[x - 3] | Equatix

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$$x=9[x-3]$$

$x = \frac{27}{8} = 3\frac{3}{8} = 3.375$

Use the distributive property to multiply $9$ by $x-3$.

$$x=9x-27$$

Subtract $9x$ from both sides.

$$x-9x=-27$$

Combine $x$ and $-9x$ to get $-8x$.

$$-8x=-27$$

Divide both sides by $-8$.

$$x=\frac{-27}{-8}$$

Fraction $\frac{-27}{-8}$ can be simplified to $\frac{27}{8}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{27}{8}$$