How to solve x = (3y - 9)/2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x = (3y - 9)/2 | Equatix

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$$x=\frac{3y-9}{2}$$

$y=\frac{2x}{3}+3$

Divide each term of $3y-9$ by $2$ to get $\frac{3}{2}y-\frac{9}{2}$.

$$x=\frac{3}{2}y-\frac{9}{2}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{2}y-\frac{9}{2}=x$$

Add $\frac{9}{2}$ to both sides.

$$\frac{3}{2}y=x+\frac{9}{2}$$

Divide both sides of the equation by $\frac{3}{2}$, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{2}y}{\frac{3}{2}}=\frac{x+\frac{9}{2}}{\frac{3}{2}}$$

Dividing by $\frac{3}{2}$ undoes the multiplication by $\frac{3}{2}$.

$$y=\frac{x+\frac{9}{2}}{\frac{3}{2}}$$

Divide $x+\frac{9}{2}$ by $\frac{3}{2}$ by multiplying $x+\frac{9}{2}$ by the reciprocal of $\frac{3}{2}$.

$$y=\frac{2x}{3}+3$$

$x=\frac{3\left(y-3\right)}{2}$