How to solve x=(z+2)/(2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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$$x= \frac{ z+2 }{ 2 }$$

$z=2\left(x-1\right)$

Divide each term of $z+2$ by $2$ to get $\frac{1}{2}z+1$.

$$x=\frac{1}{2}z+1$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}z+1=x$$

Subtract $1$ from both sides.

$$\frac{1}{2}z=x-1$$

Multiply both sides by $2$.

$$\frac{\frac{1}{2}z}{\frac{1}{2}}=\frac{x-1}{\frac{1}{2}}$$

Dividing by $\frac{1}{2}$ undoes the multiplication by $\frac{1}{2}$.

$$z=\frac{x-1}{\frac{1}{2}}$$

Divide $x-1$ by $\frac{1}{2}$ by multiplying $x-1$ by the reciprocal of $\frac{1}{2}$.

$$z=2x-2$$

$x=\frac{z+2}{2}$