Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$| x - 2 | + | x + 2 | = | \begin{array} { l } { } \end{array}$$

Answer

$$n=(DATEabs(x-2)+abs(x+2))/p-4*e^3*c*o*m*l*t^2*s$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[DATEabs(x-2)+abs(x+2)=pn+4compl{e}^{3}{t}^{2}s\]
Regroup terms.
\[DATEabs(x-2)+abs(x+2)=pn+4{e}^{3}compl{t}^{2}s\]
Factor out the common term \(p\).
\[DATEabs(x-2)+abs(x+2)=p(n+4{e}^{3}coml{t}^{2}s)\]
Divide both sides by \(p\).
\[\frac{DATEabs(x-2)+abs(x+2)}{p}=n+4{e}^{3}coml{t}^{2}s\]
Subtract \(4{e}^{3}coml{t}^{2}s\) from both sides.
\[\frac{DATEabs(x-2)+abs(x+2)}{p}-4{e}^{3}coml{t}^{2}s=n\]
Switch sides.
\[n=\frac{DATEabs(x-2)+abs(x+2)}{p}-4{e}^{3}coml{t}^{2}s\]
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