Solve x-2\div(x)^(4)-(x)^(3)-(x)^(2)-x-2=

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Question

$$x-2 \div { x }^{ 4 } - { x }^{ 3 } - { x }^{ 2 } -x-2=$$

$-x^{3}-x^{2}-2-\frac{2}{x^{4}}$

Combine $x$ and $-x$ to get $0$.

$$-\frac{2}{x^{4}}-x^{3}-x^{2}-2$$

To add or subtract expressions, expand them to make their denominators the same. Multiply $-x^{3}-x^{2}-2$ times $\frac{x^{4}}{x^{4}}$.

$$-\frac{2}{x^{4}}+\frac{\left(-x^{3}-x^{2}-2\right)x^{4}}{x^{4}}$$

Since $-\frac{2}{x^{4}}$ and $\frac{\left(-x^{3}-x^{2}-2\right)x^{4}}{x^{4}}$ have the same denominator, add them by adding their numerators.

$$\frac{-2+\left(-x^{3}-x^{2}-2\right)x^{4}}{x^{4}}$$

Do the multiplications in $-2+\left(-x^{3}-x^{2}-2\right)x^{4}$.

$$\frac{-2-x^{7}-x^{6}-2x^{4}}{x^{4}}$$

$-\frac{x^{7}+x^{6}+2x^{4}+2}{x^{4}}$