Solve x-2)+(x-3)+(x-8)=0 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x-2)+(x-3)+(x-8)=0$$

Differentiate w.r.t. x

$1$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$x^{1-1}$$

Subtract $1$ from $1$.

$$x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$1$$

Evaluate

$x-2$