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Example
3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b
Question
$$x-21=2 { x }^{ 2 }$$
Answer
x=-(-1+sqrt(167)*IM)/4,-(-1-sqrt(167)*IM)/4
Solution
Move all terms to one side.
\[x-21-2{x}^{2}=0\]
Use the Quadratic Formula.
In general, given \(a{x}^{2}+bx+c=0\), there exists two solutions where:
\[x=\frac{-b+\sqrt{{b}^{2}-4ac}}{2a},\frac{-b-\sqrt{{b}^{2}-4ac}}{2a}\]
In this case, \(a=-2\), \(b=1\) and \(c=-21\).
\[{x}^{}=\frac{-1+\sqrt{1-4\times -2\times -21}}{2\times -2},\frac{-1-\sqrt{1-4\times -2\times -21}}{2\times -2}\]
Simplify.
\[x=\frac{-1+\sqrt{167}\imath }{-4},\frac{-1-\sqrt{167}\imath }{-4}\]
\[x=\frac{-1+\sqrt{167}\imath }{-4},\frac{-1-\sqrt{167}\imath }{-4}\]
Simplify solutions.
\[x=-\frac{-1+\sqrt{167}\imath }{4},-\frac{-1-\sqrt{167}\imath }{4}\]
x=-(-1+sqrt(167)*IM)/4,-(-1-sqrt(167)*IM)/4
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