How to solve x-3 < 3-x

Q: How to solve x-3 < 3-x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x-3 < 3-x | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x-3 < 3-x$$

Solve for x

$x<3$

Solution Steps

Add $x$ to both sides.

$$x-3+x<3$$

Combine $x$ and $x$ to get $2x$.

$$2x-3<3$$

Add $3$ to both sides.

$$2x<3+3$$

Add $3$ and $3$ to get $6$.

$$2x<6$$

Divide both sides by $2$. Since $2$ is positive, the inequality direction remains the same.

$$x<\frac{6}{2}$$

Divide $6$ by $2$ to get $3$.

$$x<3$$

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Solve for x

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