$x-y=Y_{2}x+3y+8\text{ and }Y_{2}x+3y+8=0$

$\left\{\begin{matrix}x=\frac{4\left(y+2\right)}{1-Y_{2}}\text{, }&y=-\frac{8}{Y_{2}+3}\text{ and }Y_{2}\neq -3\text{ and }Y_{2}\neq 1\\x=-2\text{, }&Y_{2}=1\text{ and }y=-2\end{matrix}\right.$

$y=-\frac{8}{Y_{2}+3}$
$x=-\frac{8}{Y_{2}+3}\text{ and }Y_{2}\neq -3$