Question

$$x ( - 5 ) ^ { - x - 1 } \times ( - 5 ) ^ { 5 } = ( - 5 ) ^ { 7 }$$

Answer

$$n=25/(Fi*d*x*s*u*c*h^2*t^2*a*(-5)^(-x-1))$$

Solution


Since the power of 5 is odd, the result will be negative.
\[Findxsuchthat{(-5)}^{-x-1}\times -{5}^{5}={(-5)}^{7}\]
Simplify  \({5}^{5}\)  to  \(3125\).
\[Findxsuchthat{(-5)}^{-x-1}\times -3125={(-5)}^{7}\]
Since the power of 7 is odd, the result will be negative.
\[Findxsuchthat{(-5)}^{-x-1}\times -3125=-{5}^{7}\]
Simplify  \({5}^{7}\)  to  \(78125\).
\[Findxsuchthat{(-5)}^{-x-1}\times -3125=-78125\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[-Findxsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}\times 3125=-78125\]
Regroup terms.
\[-3125Findxsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=-78125\]
Divide both sides by \(-3125\).
\[Findxsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{-78125}{-3125}\]
Two negatives make a positive.
\[Findxsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{78125}{3125}\]
Simplify  \(\frac{78125}{3125}\)  to  \(25\).
\[Findxsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=25\]
Divide both sides by \(Fi\).
\[ndxsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{25}{Fi}\]
Divide both sides by \(d\).
\[nxsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{\frac{25}{Fi}}{d}\]
Simplify  \(\frac{\frac{25}{Fi}}{d}\)  to  \(\frac{25}{Fid}\).
\[nxsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{25}{Fid}\]
Divide both sides by \(x\).
\[nsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{\frac{25}{Fid}}{x}\]
Simplify  \(\frac{\frac{25}{Fid}}{x}\)  to  \(\frac{25}{Fidx}\).
\[nsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{25}{Fidx}\]
Divide both sides by \(s\).
\[nuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{\frac{25}{Fidx}}{s}\]
Simplify  \(\frac{\frac{25}{Fidx}}{s}\)  to  \(\frac{25}{Fidxs}\).
\[nuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{25}{Fidxs}\]
Divide both sides by \(u\).
\[nc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{\frac{25}{Fidxs}}{u}\]
Simplify  \(\frac{\frac{25}{Fidxs}}{u}\)  to  \(\frac{25}{Fidxsu}\).
\[nc{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{25}{Fidxsu}\]
Divide both sides by \(c\).
\[n{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{\frac{25}{Fidxsu}}{c}\]
Simplify  \(\frac{\frac{25}{Fidxsu}}{c}\)  to  \(\frac{25}{Fidxsuc}\).
\[n{h}^{2}{t}^{2}a{(-5)}^{-x-1}=\frac{25}{Fidxsuc}\]
Divide both sides by \({h}^{2}\).
\[n{t}^{2}a{(-5)}^{-x-1}=\frac{\frac{25}{Fidxsuc}}{{h}^{2}}\]
Simplify  \(\frac{\frac{25}{Fidxsuc}}{{h}^{2}}\)  to  \(\frac{25}{Fidxsuc{h}^{2}}\).
\[n{t}^{2}a{(-5)}^{-x-1}=\frac{25}{Fidxsuc{h}^{2}}\]
Divide both sides by \({t}^{2}\).
\[na{(-5)}^{-x-1}=\frac{\frac{25}{Fidxsuc{h}^{2}}}{{t}^{2}}\]
Simplify  \(\frac{\frac{25}{Fidxsuc{h}^{2}}}{{t}^{2}}\)  to  \(\frac{25}{Fidxsuc{h}^{2}{t}^{2}}\).
\[na{(-5)}^{-x-1}=\frac{25}{Fidxsuc{h}^{2}{t}^{2}}\]
Divide both sides by \(a\).
\[n{(-5)}^{-x-1}=\frac{\frac{25}{Fidxsuc{h}^{2}{t}^{2}}}{a}\]
Simplify  \(\frac{\frac{25}{Fidxsuc{h}^{2}{t}^{2}}}{a}\)  to  \(\frac{25}{Fidxsuc{h}^{2}{t}^{2}a}\).
\[n{(-5)}^{-x-1}=\frac{25}{Fidxsuc{h}^{2}{t}^{2}a}\]
Divide both sides by \({(-5)}^{-x-1}\).
\[n=\frac{\frac{25}{Fidxsuc{h}^{2}{t}^{2}a}}{{(-5)}^{-x-1}}\]
Simplify  \(\frac{\frac{25}{Fidxsuc{h}^{2}{t}^{2}a}}{{(-5)}^{-x-1}}\)  to  \(\frac{25}{Fidxsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}}\).
\[n=\frac{25}{Fidxsuc{h}^{2}{t}^{2}a{(-5)}^{-x-1}}\]