Question

$$x(x^{3}+4x^{2}-7x)+3x^{2}(2x^{2}-3x+4); (x^{2}-7x+1)+2x^{2}(6x-5)$$

Answer

$$x^4+4*x^3-7*x^2+3*x^2*(2*x^2-3*x+4);x^2-7*x+1+2*x^2*(6*x-5)$$

Solution


Expand by distributing terms.
\[\begin{aligned}&{x}^{4}+4{x}^{3}-7{x}^{2}+3{x}^{2}(2{x}^{2}-3x+4)\\&{x}^{2}-7x+1+2{x}^{2}(6x-5)\end{aligned}\]