How to solve x+1 < 3(x+2)+2x

Q: How to solve x+1 < 3(x+2)+2x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x+1 < 3(x+2)+2x | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x+1 < 3(x+2)+2x$$

Solve for x

$x>-\frac{5}{4}$

Solution Steps

Use the distributive property to multiply $3$ by $x+2$.

$$x+1<3x+6+2x$$

Combine $3x$ and $2x$ to get $5x$.

$$x+1<5x+6$$

Subtract $5x$ from both sides.

$$x+1-5x<6$$

Combine $x$ and $-5x$ to get $-4x$.

$$-4x+1<6$$

Subtract $1$ from both sides.

$$-4x<6-1$$

Subtract $1$ from $6$ to get $5$.

$$-4x<5$$

Divide both sides by $-4$. Since $-4$ is negative, the inequality direction is changed.

$$x>-\frac{5}{4}$$

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Solve for x

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