Solve for \(x\) in \(x+2y+1=0\).
Solve for \(x\).
\[x+2y+1=0\]
Subtract \(2y\) from both sides.
\[x+1=-2y\]
Subtract \(1\) from both sides.
\[x=-2y-1\]
\[x=-2y-1\]
Substitute \(x=-2y-1\) into \(2x-3y-12=0x\).
Start with the original equation.
\[2x-3y-12=0x\]
Let \(x=-2y-1\).
\[2(-2y-1)-3y-12=0(-2y-1)\]
Simplify.
\[-7y-14=0\]
\[-7y-14=0\]
Solve for \(y\) in \(-7y-14=0\).
Solve for \(y\).
\[-7y-14=0\]
Add \(14\) to both sides.
\[-7y=14\]
Divide both sides by \(-7\).
\[y=-\frac{14}{7}\]
Simplify \(\frac{14}{7}\) to \(2\).
\[y=-2\]
\[y=-2\]
Substitute \(y=-2\) into \(x=-2y-1\).
Start with the original equation.
\[x=-2y-1\]
Let \(y=-2\).
\[x=-2\times -2-1\]
Simplify.
\[x=3\]
\[x=3\]
Therefore,
\[\begin{aligned}&x=3\\&y=-2\end{aligned}\]
x=3;y=-2
