How to solve x + 3b ^ 0 = 2x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x + 3b ^ 0 = 2x | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x+3b^{0}=2x$$

Solve for x

$x=3$
$b\neq 0$

Steps for Solving Linear Equation

Subtract $2x$ from both sides.

$$x+3b^{0}-2x=0$$

Combine $x$ and $-2x$ to get $-x$.

$$-x+3b^{0}=0$$

Subtract $3b^{0}$ from both sides. Anything subtracted from zero gives its negation.

$$-x=-3b^{0}$$

The equation is in standard form.

$$-x=-3$$

Divide both sides by $-1$.

$$\frac{-x}{-1}=-\frac{3}{-1}$$

Dividing by $-1$ undoes the multiplication by $-1$.

$$x=-\frac{3}{-1}$$

Divide $-3$ by $-1$.

$$x=3$$

Show Solution

Solve for b

$b\neq 0$
$x=3\text{ and }b\neq 0$

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Example

Question

Solve for x

Steps for Solving Linear Equation

Solve for b